4p^2-12p=55

Solution for 4p^2-12p=55 equation:

4p^2-12p=55

We move all terms to the left:

4p^2-12p-(55)=0

a = 4; b = -12; c = -55;
Δ = b2-4ac
Δ = -122-4·4·(-55)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-32}{2*4}=\frac{-20}{8}
=-2+1/2
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+32}{2*4}=\frac{44}{8}
=5+1/2
$